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arcserve-KB : What is your current latency or round trip time reported by a ping test with payload?

Last Update: 2015-08-13 19:45:41 UTC

What is your current latency or round trip time reported by a ping test with payload?

 Run this command:

ping –n 50 –l 512 <ipaddress>

 This will send 50 packets of size 512 bytes to the ip address provided.  The resulting summary information at the end of the ping test will provide an average RTT which can then be used to determine the Maximum Theoretical Throughput.

 As an example:

 When using a Windows client with a 256KB TCPSendReceive window (RHA Default TCP Send/Recv Window is 256K) over a 100 Mbps WAN with a 50 ms delay/RTT, the maximum throughput for a single TCP connection would be:

 Max. throughput = 256 KB * (8 bits/byte) / 0.050 sec = 40,960 Kbps = 40.960 Mbps – This is less than your available bandwidth which means multiple streams would help.

 If you assume 72 ms delay/RTT:

Max. throughput = 256 KB * (8 bits/byte) / 0.072 sec = 28,444 Kbps = 28.44 Mbps – This is less than your available bandwidth which means multiple streams would help.

 If you assume a 10 ms delay/RTT:

Max. throughput = 256 KB * (8 bits/byte) / 0.010 sec = 204,800 Kbps = 204.80 Mbps – This exceeds available throughout and more streams would not help.

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